1.807=0.016(x)^2+0.124(x)+0.787

Solution for 1.807=0.016(x)^2+0.124(x)+0.787 equation:

1.807=0.016(x)^2+0.124(x)+0.787

We move all terms to the left:

1.807-(0.016(x)^2+0.124(x)+0.787)=0

We get rid of parentheses

-0.016x^2-0.124x-0.787+1.807=0

We add all the numbers together, and all the variables

-0.016x^2-0.124x+1.02=0

a = -0.016; b = -0.124; c = +1.02;
Δ = b2-4ac
Δ = -0.1242-4·(-0.016)·1.02
Δ = 0.080656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.124)-\sqrt{0.080656}}{2*-0.016}=\frac{0.124-\sqrt{0.080656}}{-0.032}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.124)+\sqrt{0.080656}}{2*-0.016}=\frac{0.124+\sqrt{0.080656}}{-0.032}
$